consider the reaction H2Xg HXg Xg delta H0 184 kJmol delt

consider the reaction

H2X(g) ? HX(g) + X(g)

                                 delta H^0<?xml:namespace prefix = v ns = \"urn:schemas-microsoft-com:vml\" /> <?xml:namespace prefix = o ns = \"urn:schemas-microsoft-com:office:office\" /> = 18.4 kJ/mol delta S^0 = 23.1 J/mol-K

What is Keq for this reaction at 525 K?

I used the following formulas to solve for Keq, but not getting the right answer :/, I also made sure that everything was in kJ

    DG⁰ = DH⁰

Solution

Delta G0 = delta H0 -T* delta S0 = 18.4 - 525*23.1/1000 = 6.2725 KJ/mol

Delta G0 = -RTln(Keq)

Keq = e^(-Delta G0/RT) =0.23763 M