4 How many milliliters of 00844 M BaOH2 are required to titr
Solution
Ans 4
Calculuate number of moles of HNO3 you are going to titrate:
 Molarity X Volume = moles
 (0.0526M) X (.050L) = .00263 moles of HNO3
Ba(OH)2 + 2HNO3 -> 2H2O + Ba(No3)2
we can see that 2 moles of HNO3 neutralizes one mole of Ba(OH)2 .
So, .00263 moles of HNO3 will neutralise (1/2)*0.00263 moles of Ba(OH)2
0.00131 moles of Ba(OH)2
There are TWO OH- in Ba(OH)2 so concentration of OH- is two times concentration ofBa(OH)2 : 2( 0.0844M )= 0.169M
volume in liters = moles/Molarity
(.00131 moles)/(.169M) = 7.75X10^-3 L = 7.75mL
ans 5.
a) AgNO3 + CuCl2 -> AgCl2 + Cu(NO3)2
b) Net ionic equation
 2Ag+(aq) + 2Cl-(aq) --> 2AgCl(s)
 simplify:
 Ag+(aq) + Cl-(aq) --> AgCl(s)
c)complete ionic equation:
 2Ag+(aq) + 2NO3-(aq) + Cu2+(aq) + 2Cl-(aq) --> 2AgCl(s) + Cu2+(aq) + 2NO3-(aq)
ans
a) CaSO3(s)+2HBr(aq)CaBr2(aq)+SO2(g)+H2O(l)
b) total ionic equation
 CaSO3(s) + 2H+(aq) + 2Br-(aq)  Ca2+(aq) + 2Br-(aq) + SO2(g) + H2O(l)
c) ionic equation
CaSO3(s)+2H+(aq)Ca2+(aq)+SO2(g)+H2O(l)

