Questlon 3 1 point Let segments AP and BP be tangent segment
   
Solution
Q3) Tangents drawn from a point outside a circle are equal. AP = BP
Therefore 3x - 10 = 8x - 15. Solving 5x = 5 or x = 1 (Option 1)
Q4) Tangents drawn from a point outside a point are equal. AP = BP
 Therefore 3x + 10 = 8x - 15. Solving 5x = 25, Therefore x = 5
Therefore AP = 3x + 10 = (3*5) + 10 = 15 + 10 = 25 cm (Option 3)
Q5) By the internal intersection of secants theorem:
AE * EB = CE * ED
Therefore 8 * 5 = CE * 10. Or CE = 4 inches (Option 1)
Q6) By the internal intersection of secants theorem:
AE * EB = CE * ED
(x+2) * 8 = 3x * 4
Therefore 8x + 16 = 12x
4x = 16
x = 4 mm (Option 1)

