At 453 K this reaction has a Ko value of 00755 Calculate Kp

At 453 K, this reaction has a Ko value of 0.0755. Calculate Kp at 453 K Number Note that the pressure is in units of atmosphere (atm) Tools x 102

Answer:

Given reaction is

X(g) + 2Y(g) -------> 2Z(g)

Given Kc=0.0755.

Kp=? T=453 K.

Kp=Kc (RT)^n

Where R=gas constant=0.0821 L atm/mol.K

n=(sum of moles of gaseous products) - (sum of moles of gaseous reactants)=(2) - (1+2)=2-3=-1.

Therefore Kp=Kc(RT)^-1

Kp=Kc/RT=(0.0755)/(0.0821 x 453K)

Kp=2.03 x 10^-3.