15 and 17 7x 2 e17x 2x 1 eln x2Solution15 7x2 e17x apply

15 and 17?

7^x + 2 = e^17x 2x - 1 = e^ln x^2

15) 7^(x+2) =e^(17x)

apply natural log both sides we get,

(x+2)*ln(7)=17x

xln7+2ln7=17x

17x-xln7=2ln7

x(17-ln7)=2ln7

x=2ln7/(17-ln7) answer

17) 2x-1 = e^(lnx^2)

we know that e^(lnx) = x

so we will have

2x-1 = x^2

x^2 -2x+1=0

(x-1)^2=0

x=1 answer