The Independent Bank surveyed the status of student accounts

The Independent Bank surveyed the status of student accounts and found that the average overdraft was $24.33 with a standard deviation of $5.87. If the distribution is normal, find the probability of a student being overdrawn by more than $21.69.

P=?

Solution

Normal Distribution
Mean ( u ) =24.33
Standard Deviation ( sd )=5.87
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
P(X > 21.69) = (21.69-24.33)/5.87
= -2.64/5.87 = -0.4497
= P ( Z >-0.45) From Standard Normal Table
= 0.6736