Q1 Deposit 1000 at the end of each month for next 10 years h
Q1: Deposit $1,000 at the end of each month for next 10 years, how much money will I have at the end of 10 years in the following scenarios?
A: 6% interest per year compounded monthly.
B: 8%: interest per year compounded monthly.
Q2: Deposit $1,000 at the end of year 1 and increment the deposit by $100 for the next 4 years, how much money will I have at the end of 5 years in the following scenario?
C: 9% interest per year compounded continuously.
Q3: What is a real-life application of continuous compounding?
Solution
Q1.
A. Monthly interest rate = 6%/12 = 0.5%
Compound interest factor = ((1 + i)n - 1) / i = ((1+0.5%)120 - 1)/0.5% = 163.88 , (for 10 years, numbe rof monthly time periods = 10*12 = 120
Fund value at the end of 10 years = 1000*163.88 = 163,880
B. Monthly interest rate = 8%/12 = 0.67%
Compound interest factor = ((1 + i)n - 1) / i = ((1+0.67%)120 - 1)/0.5% = 182.95 , (for 10 years, numbe rof monthly time periods = 10*12 = 120
Fund value at the end of 10 years = 1000*182.95 = 182,950
