Solve the system of equations y x 2x 3 y x 1 Solve the

Solution

Given equations are y = x² + 2x - 3

y = x - 1

Substitute y=x-1 in y = x² + 2x - 3

y = x² + 2x - 3

x-1 = x² + 2x - 3

x² + 2x - 3-x+1=0

x² + x - 2=0

x² + 2x -x - 2=0

x(x+2)-1(x+2)=0

(x+2)(x-1)=0

x+2=0 or x-1=0

x=-2 x=1

when x=-2, y=x-1

y=-2-1

y=-3

when x=1, y=x-1

y=1-1

y=0

Therefore, Solution of the system of equations is (-2,-3) and (1,0)