fx3x2 ex find any critical values find any hypercritical val

Solution

y = e^(5x) y\' = 5e^(5x) Sample2: y = e^(5x^2) y\' = 10xe^(5x^2) You must take the derivative of the expression raised in the exponential, and multiply it in front. y = e^(3x^2+x) y\' = (6x+1)e^(3x^2+x) y\'(2)=13e^(14)