a line passes through the point 23 and has a slope 5 Write a

a line passes through the point (-2,3) and has a slope 5. Write an equation for this line.

We have given point (x1,y1) = (-2,3) and slope m = 5.

Point-slope formula of equation of line is : (y - y1) = m(x - x1)

Now plug the values in the equation.

So it becomes , (y - 3) = 5(x - (-2))

So y - 3 = 5(x+ 2)

Simplfy this now.

y - 3 = 5x + 10

Therefore , y = 5x + 10 + 3

y = 5x + 13

This is the equation of line.