In the days before scuba gear some divers descended to under

In the days before scuba gear, some divers descended to underwater depths in diving bells, which are basically just upside-down containers whose open ends face down (towards the water; see the illustration below). The bell allows the person inside to breathe the air trapped inside it, observe underwater objects and marine life, and work under the water. If the bell is submerged to a depth of 30m below sea level, what is the water presure outside the bell? If the air pressure inside the bell before submersion into the water was 1 atm (101.825 kPa), what air pressure does the person experience at that depth? can someone explain it in detail and show every step in how to do it please?

Solution

Here ,

depth , d = 30 m

Po = 1 atm

Po = 1.018 *10^5 Pa

for the water pressure outside the well = Po + p * g *d

water pressure outside the well = 1.018 *10^5 + 1000 * 9.8 * 30

water pressure outside the well = 3.958 *10^5 Pa

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as the inside the bell , the air pressure must be same as the air pressure due to water.

the air pressure inside the bell = 3.958 *10^5 Pa