And please explain it clearly write a program that calculate
Solution
/* Program is given below variable amt is for amount of numbers, array num[] for storing numbers, sum and temp are temporary variable */
#include <iostream>
using namespace std;
int main()
 {   int amt,i,num[50];
     int sum=0;
     float mean,temp=0,variance;
    //prompt user to enter total amount of numbers
     cout << \"Enter total numbers:\";
     cin>>amt;
//accept numbers from user and store it in num[]
     cout<<\"Enter Numbers:\";
     for(i=0;i<amt;i++)
      cin>>num[i];
      //calculate Mean
     for(i=0;i<amt;i++)
       sum+=num[i]; //adding total numbers in array
     mean = (sum/amt); //calculate mean by dividing sum by amt
    cout<<\"Mean is :\"<<mean<<endl;
    // calculate Variance
    for(i=0;i<amt;i++)
    { //calulate numerator part of variance formula and store in temp
        temp += (num[i] - mean) * (num[i] - mean);
    }
 variance = temp/(amt-1); //Variance
 cout<<\"Variance is :\"<<variance<<endl;
 
    return 0;
 }
Output:
Test case 1:
sh-4.2$ main
Enter total numbers:5
Enter Numbers:1 2 3 4 5
Mean is :3
Variance is :2.5
Test case 2:
Enter total numbers:5
Enter Numbers:4 6 8 10 12
Mean is :8
Variance is :10


