And please explain it clearly write a program that calculate
Solution
/* Program is given below variable amt is for amount of numbers, array num[] for storing numbers, sum and temp are temporary variable */
#include <iostream>
using namespace std;
int main()
{ int amt,i,num[50];
int sum=0;
float mean,temp=0,variance;
//prompt user to enter total amount of numbers
cout << \"Enter total numbers:\";
cin>>amt;
//accept numbers from user and store it in num[]
cout<<\"Enter Numbers:\";
for(i=0;i<amt;i++)
cin>>num[i];
//calculate Mean
for(i=0;i<amt;i++)
sum+=num[i]; //adding total numbers in array
mean = (sum/amt); //calculate mean by dividing sum by amt
cout<<\"Mean is :\"<<mean<<endl;
// calculate Variance
for(i=0;i<amt;i++)
{ //calulate numerator part of variance formula and store in temp
temp += (num[i] - mean) * (num[i] - mean);
}
variance = temp/(amt-1); //Variance
cout<<\"Variance is :\"<<variance<<endl;
return 0;
}
Output:
Test case 1:
sh-4.2$ main
Enter total numbers:5
Enter Numbers:1 2 3 4 5
Mean is :3
Variance is :2.5
Test case 2:
Enter total numbers:5
Enter Numbers:4 6 8 10 12
Mean is :8
Variance is :10

