A proton is confined in a space of length 31015 m The minimu

A proton is confined in a space of length 3*10^-15 m. The minimum uncertainty in measuring its momentum is approximately

Solution

delta x = 3 * 10^-15 m

h   = 6.63 * 10^-34 J

From uncertainity, delta x * delta P > h / 2 pi

delta P = h / 2 pi * delta x

= ( 6.63 * 10^-34 ) / ( 2 pi * 3 * 10^-15 )

delta P = 3.52 * 10^-20 Kg m/s