Calculate the ph of 67 m of hno3 ThanksSolutionNaOHNa OH si

Calculate the ph of .67 m of hno3.

Thanks

Solution

NaOH----->Na+ + OH-
since it is a strong base the [OH-]=0.67 pOH=-log[OH]=-log[0.67]

pH = log ( 1/ [ H+] )
pOH = log (1/ [ OH-])
pH + pOH = 14

pH + pOH=14 you can find using these.

HNO3 is also a strong acid so pH=-log[H+]=-log[0.017]