6a3 2a2 divided by 4a denominators denominator 9a2 1 divide

6a3 - 2a2 divided by 4a

denominators denominator

9a2 -1 divided by 15a +5

These are 2 fractions that are divided by each other

Solution

==>6a^3 - 2 a^2 / 4a /9a^2-1/15a+5

==> 6a^3 - 2 a^2 / 4a * 15a+5 /9a^2-1

==> 2a^2 ( 3a - 1 ) / 4a * 5 ( 3a + 1 ) / ( 3a + 1 ) ( 3a - 1 )

==> a ( 3a - 1 ) / 2 * 5 / ( 3a - 1 )

==> 5a ( 3a - 1 ) / 2( 3a - 1 )

==>5a / 2

6a3 - 2a2 divided by 4a denominators denominator 9a2 -1 divided by 15a +5 These are 2 fractions that are divided by each otherSolution==>6a^3 - 2 a^2 / 4a /9

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site