log3 log4 256x 4SolutionApplying log rule a logbba we get

log_3 (log_4 (256x)) = 4

Solution

Applying log rule : a = logb(ba)

we get 4 = log3(34)

Hence : log3(log4(256x) = 4 can be written as log3(log4(256x) = log3(34)

As the logs have same base on both sides , the functions will be equal.

Hence we get (log4(256x) = 34 = 81

Using a = logb(ba) we get 81 = log4(481)

As logs have same bases on both sides , the functions wll be equal.

Hence we get (log4(256x) = log4(481)

Hence (256x) = (481)

Hence (28) x = 2162

Hence x = 2(162 - 8) = 2154

Hence x = 2154

 log_3 (log_4 (256x)) = 4SolutionApplying log rule : a = logb(ba) we get 4 = log3(34) Hence : log3(log4(256x) = 4 can be written as log3(log4(256x) = log3(34) A

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