Suppose that the graph of f contains the point 36 Find a poi

Suppose that the graph of f contains the point (3,6). Find a point that must be on the graph of g(x)=f((x+2)/(5))

Given that the graph of f contains the point (3,6).

i.e., f(3)=6

Need to find a point that must be on the graph of g(x)=f((x+2)/(5)).

Let (x+2)/(5) = 3

x+2 = 3*5

x+2 = 15

x = 15-2

x=13

Now x=13 in g(x)=f((x+2)/(5))

g(13)=f((13+2)/(5))

=f((15)/(5))

= f(3)

= 6

Therefore, a point on the graph of g(x)=f((x+2)/(5)) is (13,6)