A small particle has charge 250 mu C and mass 0150 g It move

A small particle has charge +2.50 mu C and mass 0.150 g. It moves from point k where the electric potential is -333 V to point B where the electric potential is -444 V. How much work is done on this particle by the electric force?

Solution

Work done by electric field = change in Kinetic Energy

w=-q*dV

W=2.50(-444+333)*10^-6

W=2.775*10^-4 Joules ans