Empirical Gas Laws 539 Suppose you had a 410L sample of neon

Empirical Gas Laws 5.39 Suppose you had a 4.10-L sample of neon gas at 21°C and a pressure of 0.959 atm. What would be the volume of this gas if the pressure were increased to 1.210 atm while the temperature remained constant?

Solution

for tempreture is constant then use formula

We know that Boyl\'s law

P₁V₁ = P₂V₂ then

V₂ = P₁V₁/P₂ where

P₁ = initial pressure = 0.959 atm

V₁ = initial volume = 4.10 ml

P₂ = final pressure = 1.210 atm

V₂ = final volume = ?

Substitute these value in above equation

V₂ = 0.959 X 4.10/1.210 = 3.25 L

If the pressure is adjusted to 1.210 atm volume of neon gas is = 3.25 L