ID96552057 next of H2 produced aqueous solutions of NaCl to

ID-96552057 next of H2 produced aqueous solutions of NaCl to give Clz, Ha, and NaOH 2NaCl(ag) +2H20(0)-2NaOH(aq) +H2(g)+Cl2(9) of NaOH produced

The reaction is

2 NaCl + 2 H2O -----------> 2 NaOH + Cl2 + H2

Part A)

Thus for each mole of Cl2 produced, one mole of H2 is also produced.

Thus the moles of Cl2 = moles of H2 produced.

moles of Cl2 = mass/ molar mass

= 1.6x 10⁹ g /71 g [ mass to be taken in g not in Kg]

= 0.0225 x10⁹ moles

Thus the mass of H2 produced = moles of H2 x molar mass

= 0.0225 x10⁹ mol x 2 g/mol

=0.045 x10⁹ g

= 4.5x10⁷g

= 4.5x10⁴ kg of H2 gas

The quantity of H2 produced =4.5x10⁴ kg

Part B

From the balanced equation

for each mole of CL2 produced , 2 moles of NaOh is formed.

thus moles of NaOH formed = 2 x moles of Cl2

= 2 x 0.0225 x10⁹ moles

Mass of NaOH formed = molar mass x moles of NaOH

= 40g/mol x 2 x 0.0225 x10⁹ moles

= 1.803x10⁹g

= 1.803x10⁶ kg of NaOH

Thus the quantity of NaOh produced = 1.803x10⁶ kg of NaOH