A 2B 3 C productsSolutionconsider run 1 and run 4 only c
A + 2B + 3 C = products
Solution
consider run 1 and run 4
only c changes.but no effect on rate. so rate independent of C.
consider run 3 and 4
only A changes by factor of 1/3 and rate changes by factor of 1/3
so rate is proportional to [A].
consider run 2 and 5
only B changes by factor of 1/2 and rate by factor of 1/4 so
rate is proportional to [B]^(2)
so rate=K*[A]*[B]^(2)
K=5/(0.2*0.1^(2))=2500
so rate=2500*[A]*[B]^(2)
