A 2B 3 C productsSolutionconsider run 1 and run 4 only c


A + 2B + 3 C = products

Solution

consider run 1 and run 4

only c changes.but no effect on rate. so rate independent of C.

consider run 3 and 4

only A changes by factor of 1/3 and rate changes by factor of 1/3

so rate is proportional to [A].

consider run 2 and 5

only B changes by factor of 1/2 and rate by factor of 1/4 so

rate is proportional to [B]^(2)

so rate=K*[A]*[B]^(2)

K=5/(0.2*0.1^(2))=2500

so rate=2500*[A]*[B]^(2)


 A + 2B + 3 C = productsSolutionconsider run 1 and run 4 only c changes.but no effect on rate. so rate independent of C. consider run 3 and 4 only A changes by

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