i average rate of change from x6 to x10 AM first day ii aver

(i) average rate of change from x=6 to x=10 AM (first day)

(ii) average rate of change from x=10 to x= 12 AM

(iii) average rate of change from x=6 to x=12

500 400 2 300 200 100 + 6 9 12 3 6 9 12 3 6 Time

Solution

Since the points at time x = 6 , 10 are not given in graph only approximate results can be found

(i) average rate of change from x=6 to x=10 AM (first day)

x = 6   f(x) = 480 ; x = 10 f(x) = 400

Avg rate = (f(x2) - f(x1) )/(x2 - x1) = ( 400-480)/10 -6 = -20

(ii) average rate of change from x=10 to x= 12 AM

x =10 f(x) = 400 ; x = 12 f(x) = 150

Avg rate = (f(x2) - f(x1) )/(x2 - x1) = ( 150 -400)/( 12 -10) = -125

(iii) average rate of change from x=6 to x=12

x = 6 f(x) = 480 ; x =12 f(x) = 150

Avg rate = (f(x2) - f(x1) )/(x2 - x1) = ( 150 - 480)/( 12 -6) = -55

(i) average rate of change from x=6 to x=10 AM (first day) (ii) average rate of change from x=10 to x= 12 AM (iii) average rate of change from x=6 to x=12 500 4

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