The width of a rectangle is 6 less than twice its length If

The width of a rectangle is 6 less than twice its length. If the area of the rectangle is 172 cm2 whatis the length of the diagonal? The length of the diagonal is cm. Give your answer to 2 decimal places Get help: Video Points possible: 10 This is attempt 1 of 2. Message instructor about this question Post this question to forum e Submit jump to Answer

Solution

width = 2*length - 6

Area = 172

w*l = 172 ; (2l -6)*l = 172

2l^2 - 6l - 172 =0

l^2 - 3l - 86 =0

l = 10.89 , - 7.89 ( neglect -ve)

l = 10.89 ; w = 15.78

diagonal = sqrt( l^2 + w^2) = sqrt(10.89^2 + 15.78^2) = 19.17