Please help me with problem 37 Written if possible step by s

Solution

37) x^3 - 8 =0

x^3 - (2)^3 =0

(x - 2)(x^2 + 2x + 4) =0

x = 2

x^2 +2x +4 =0

sove using quadratic formula : x = ( -2 +/- sqrt( 4 - 4*4) )/2

x = -1 +/- i*sqrt(3)

So roots are x = 2 , -1 + isqrt3 , -1 - isqrt3