Please help and show work please 1 Given the hypotenuse 10
Please help and show work please
1. Given the hypotenuse = 10 m, angle = 30º, find the length of both legs of the triangle.
2. Given angle = 55º, opposite side = 4 m, find the hypotenuse and adjacent side lengths.
3. Given the hypotenuse = 4 m, side A = 3 m, find both acute angles.
4. Given the length of the side A = 3 m, and side B = 5 m, find the acute angles and the hypotenuse.
5. A ball is kicked into the air at an angle of 25º to the horizontal with an initial resultant velocity of 25 m/sec.
6. Find both the vertical and horizontal components of the velocity vector.
7. At the instant of takeoff, a long jumper has a forward velocity of 9.47 m/sec and a vertical velocity of 3.21 m/sec.
8. Find the angle of takeoff (relative to the horizontal) and the magnitude of the resultant velocity vector.
Solution
Hypotenuse=10m and alpha=30degree
sin alpha=opposite/hypotenuse
sin 30=opposite/10
1/2=opposite/10
opposite=5
cos alpha=adjacent/hypotenuse
cos30=adjacent/10
adjacent=10*(sqrt3/2)
adjacent=5sqrt3
2. alpha=55degree and opposite=4m
sin alpha=opposite/hypotenuse
sin55=4/hypotenuse
hypotenuse=4/sin55
hypotenuse=4.883 m
cos alpha=adjacent/hypotenuse
cos 55=adjacent/4.883
adjacent=4.883*cos 55=2.8
