1 Solve the triangle Make sure to check if there is 1 2 or n

1) Solve the triangle. (Make sure to check if there is 1, 2, or no triangle).

A=36 degrees, a = 30, b = 2

given A=36^o, a = 30, b = 2

by law of sines a_/sinA=b_/sinB=c_/sinC

=>30_/sin36^o=2_/sinB=c_/sinC

=>30_/sin36^o=2_/sinB

=>sinB=(2_/30)sin36^o

=>B=2.24575^o,177.75425^o

A+B+C=180° ,B=2.24575^o

=>36^o+2.24575^o+C=180^o

=>C= 141.75425^o approximately

30_/sin36^o=c_{/sin141.75425^o}

=>c=30sin141.75425^o_/sin36^o

=>c=31.595

no triangle possible with B=177.75425^o

so there is only one triangle possible

A=36^o, a = 30, b = 2 ,B=2.24575^o,C= 141.75425^o,c=31.595

you can roundoff the answers to you your required number of decimals as needed