Find the vertex of the parabola gx x2 3x 6SolutionAnswer

Find the vertex of the parabola g(x) = x^2 - 3x + 6

Solution

Answer: Vertex of the given parabola is (3/2, -6) (As explained below)

If the equation of the parabola be Ax² + Bx + C = 0, then:

Vertex = (h,k) = (-B/2A, -B² - 4AC / 4A)

So, our equattion of the parabola is x² - 3x + 6.

So, A = A; B = -3 and C = 6.

So, the vertex = (-(-3)/2(1), -4(1)(6) / 4(1)) = (3/2, -6)