In a transformation experiment DNA of a pq strain was used t
In a transformation experiment, DNA of a p+q+ strain was used to transform a recipient strain that is auxotrophic for these markers. The number of each class of transformants is shown below:
Class
Genotype
Number
1
p+q+
405
2
p+q–
300
3
p–q+
195
4
p–q-
680
What is the map distance between these two loci? (2 points)
| Class | Genotype | Number |
| 1 | p+q+ | 405 |
| 2 | p+q– | 300 |
| 3 | p–q+ | 195 |
| 4 | p–q- | 680 |
Solution
Answer:
The parental combinations are p+q+ & p-q- = 405+680 = 1085
The recombinants are p+q- & p-q+ = 300 + 195 = 495
The recombination frequency(RF) = (recombinant progeny/total progeny)100
RF = (495/1580)100
RF = 31.33%
(%) RF = (map units) Distance between the genes (loci)
31.33% = 31.33 map units
So the distance between the two loci is 31.33 map units
