The sum of four consecutive odd integers is 112 What is the
     The sum of four consecutive odd integers is 112. What is the greatest of these four integers? (Given to seventh-and eighth-grade students) 
  
  Solution
we need to find the greatest of 4 odd integers if sum of 4 odd consecutive integers is 112
let assume that x is the smallest odd integer we know that x is the current odd integer then x+2 is the next odd integer , x +2+2= x+4 is the next to next odd integer and so on
assume that x is the first that is smallest odd integer of 4 integers so
x+2 is the second odd integers
x+4 is the third odd integer
x+6 is the fourth that is greatest odd integer.
as given sum of them is 112
so add the togather we have,
x + x + 2 + x + 4 + x + 6 = 112
4x + 12 = 112
4x = 100
x = 25
so smallest odd integer is 25 and greatest odd integer is x + 6 = 25 + 6 = 31

