vx t 000 to 200 s vx t 200 to 1600 s vx t 1600 to 1700 s

v_x (t = 0.00 to 2.00 s) v_x (t = 2.00 to 16.00 s) v_x (t = 16.00 to 17.00 s) What is the acceleration of the train during the 14.00-s interval? m/s^2

Solution

Accelaration of the train during 14 sec interval :

velocity during 14 sec interval

= s/t = 11.5/14 = 0.8214 m/sec

so, accelaration = v/t

0.8214/14 = 0.0586 m/s^2