Express the inverse Laplace Transform as a convolution and t

Express the inverse Laplace Transform as a convolution and then compute the corresponding convolution integral to find the inverse Laplace Transform.

inverse Laplace of {1/(s+1)(s-2)}

1/(s+1)(s-2)=1/3(s-1) -1/3(s+2); by partial fraction

Take lminverse laplace

L^-1(1/3(s-1))=1/3(e^t)

L^-1(1/3(s+2))=1/3(e^-2t)

L^-1(1/(s-1)(s+2))=1/3{e^t-e^-2t}