Suppose a womens college basketball player is fouled in a on

Suppose a women’s college basketball player is fouled in a one-and-one situation (meaning she is awarded two free throws only if she makes her first one). Assume that her season average for free throws is 70%. We know that only three following scenarios are possible: A) she makes both, B) she makes the first and then misses the second, or C) she misses the first. Place these three scenarios (A, B, and C) into the order of most likely to happen down to the least likely to happen. (Hint: use a probability tree to help you find the answer. See the video clip below if you need some help calculating the probabilities of the three different scenarios by looking at a slightly different example.)

Solution

P(making the throws) = 0.7

P(missing the throws) = 1 - 0.7 = 0.3

P(A) = 0.7 * 0.7 = 0.49

P(B) = 0.7 * 0.3 = 0.21

P(C) = 0.3

So, the order is A, C, B