Chapter 6 Section 63 Go Tut Problem 002 The graph of gx cont

Chapter 6, Section 6.3, Go Tut Problem 002

The graph of g(x) contains the point (7, –78). Find a point of the graph of ( g ( 1/3 (x+4) ) 8 ).

( ___ , ___ )

g(x) contains (7,-78)

this means

g(7) = -78

y = - (g(1/3(x+4) ) - 8 )

so we need to find x when

- (g(1/3(x+4) ) - 8 ) = g(7)

- (1/3(x+4) ) = 7

solving for x

x = 17

plugging g(7) = -78

-(g(1/3( 17+4) ) - 8

y = - (g(7) - 8 )

y = - (-78) - 8 )

y = 70

hence, graph of ( g ( 1/3 (x+4) ) 8 ) contains ( -78 , 70 )