The equilibrium constant Kc for the following reaction is 11

The equilibrium constant, Kc, for the following reaction is 1.10x10 at 447 K PCIs(g)--PCI3(g) + Cl2(g) When a sufficiently large sample of PCl5(g) is introduced into an evacuated vessel at 447 K, the equilibrium concentration of Cl2(g) is found to be 0.391 M. Calculate the concentration of PCl5 in the equilibrium mixture. Submit Answer Retry Entire Group 3 more group attempts remaining

Solution

Answer

[PCl5] = 139M

Explanation

PCl5(g) < - - - - - > PCl3(g) + Cl2(g)

Kc = [PCl3][Cl2] /[PCl5] = 1.10×10^-3

at equillibrium

[PCl3] = [Cl2] = 0.391M

(0.391M)² / [PCl5] = 1.10×10^-3M

[PCl5] = (0.391M)²/1.10×10^-3M = 1.39×10²M