According to a survey the probability that a randomly select

According to a survey, the probability that a randomly selected worker primarily drives a van to work is 0.737. The probability that a randomly selected worker primarily takes public transportation to work is 0.100. Complete parts (a) through (d).

Solution

(a)

P(worker drives a van or takes pubic transport to work) = 0.737+0.100 = 0.837

(b)

P(neither worker drives a van nor takes pubic transport to work) = 1 - 0.837 = 0.163

(c)

P(worker does not drive a van to work) = 1 - P(worker drives a van to work) = 1 - 0.737 = 0.263

(d)

Option A is correct.