Homework SourseWhat is the pH of a 0014 M CaOH2 solutionSolutionCaOH2 is a
What is the pH of a 0.014 M Ca(OH)2 solution?
Solution
Ca(OH)2 is a strong electrolyte and dissociate completely to Ca2+ and 2 OH- ions
[OH-] = 2 * 0.014 = 0.028 M
pOH= -log[OH-]
pOH = -log(0.028)
pOH = -(-1.55) = 1.55
pH + pOH = 14.0
pH + 1.55 = 14.0
pH = 14.0 - 1.55 = 12.45
Therefore, pH of a 0.014 M Ca(OH)2 solution = 12.45
![What is the pH of a 0.014 M Ca(OH)2 solution?SolutionCa(OH)2 is a strong electrolyte and dissociate completely to Ca2+ and 2 OH- ions [OH-] = 2 * 0.014 = 0.028](/WebImages/39/what-is-the-ph-of-a-0014-m-caoh2-solutionsolutioncaoh2-is-a-1118758-1761594849-0.webp "What is the pH of a 0.014 M Ca(OH)2 solution?SolutionCa(OH)2 is a strong electrolyte and dissociate completely to Ca2+ and 2 OH- ions [OH-] = 2 * 0.014 = 0.028")
