FIRST TRIAL SECOND TRIAL 1 Mass of crucible and lid 2 Mass o

FIRST TRIAL SECOND TRIAL 1 Mass of crucible and lid 2 Mass of crucible, lid, Mg 3 Mass of Mg used 4Mass of crucible, lid, product 0.1 0.242 (lt weighing) Mass of crucible, lid, product (2 weighing) 6 Mass of product .5109 9 10 11 Mass of O reacted % (m/m) Mg %(m/m) Moles of Mg Moles of O EMPIRICAL FORMULA CALCULATIONS: EXPERIMENT4 91

Solution

The reaction happening will be

2Mg(s) + O2(g) ------- 2MgO(s)

Number of moles ratio in both trials is 1:1

Hence the formula of the compound will be MgO

		FIRST TRIAL	SECOND TRIAL
	Mass of crucible and lid	77.464g	78.356g
	Mass of crucible, lid and Mg	77.654g	78.598g
	Mass of Mg used	0.190g	0.242g
	Mass of crucible lid and Product (1st weighing)	77.774g	78.748g
	Mass of crucible lid and Product (2nd weighing)	77.785g	78.738g
	Mass of Product	0.310g	0.392g
	Mass of O reacted	0.120g	0.150g
	% (m/m) by Mg	61.209%	61.73%
	% (m/m) by O	38.701%	38.27%
	Moles of Mg	0.0078	0.00995
	Moles of O	0.0075	0.009375