Please help and show your work Crl3 KOH Cl2K2Cr2O7 KlO4
Please help and show your work
Crl3 + KOH + Cl2--->K2Cr2O7 + KlO4 + KCl + H2O
Oxidation Half Rx: CrI3--->Cr2O72- + IO4-
Reduction Half Rx: Cl2--->2Cl-
Solution
2 CrI3 + 62 KOH + 27 Cl2 = K2Cr2O7 + 6 KIO4 + 54 KCl + 31 H2O
