Find the equation of the line that is perpendicular on the l

Find the equation of the line that is perpendicular on the line x - 3y = 1 and is passing through the point (-2, 3)

perpendicular to x - 3y = 1

finding slope of the line

3y = x - 1

y = x/3 - 1/3

slope = 1/3

slope of perpendicular line is negative reciprocal of this

hence slope of perpendicular line would be -3

passes throgh (-2,3)

point slope form of line is

y -y1 = m( x- x1)

plugging the values we get

y + 2 = -3 ( x-3)

y + 2 = -3x + 9

hence equation of line is

y = -3x + 7