Find the first partial derivatives of the function u xyZ ux

Find the first partial derivatives of the function.
u= x^(y/Z)
?u/?x=
?u/?y=
?u/?z=

u/x= (y/z)*x ^(y/z-1)

lnu = (y/z)lnx
1/u *u/y= lnx/z ;
so
u/y= x^(y/Z)* lnx/z ;

1/u*u/z= -ylnx/z² ;

so u/z= - x^(y/Z) *ylnx/z²