Triangle ABC has vertices A 61 B 29 and C 85 Answer the foll
Triangle ABC has vertices A (6,1), B (2,-9) and C (-8,5). Answer the follwoing questions.
a) Find the length of side AB (found it, AB = sqrt 116 )
b) Find the Angle A to the nearest degree
c) find the length of the median from the vertex C.
Solution
a)AB =116 = 10.77
BC =17.2
AC = 14.56
b)using cos rule
cosA =[AC^2 +AB^2-BC^2]/2AC*AB =0.1025
hence angle A = 84.16 degrees
C)mid point of AB =(4,-4)
hence length median = 15

