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Solution
f(x) =x3-5x2+7x-11
f|(x)=3x2-10x+7
f|(0)=3(0)-10(0)+7
=7
f|(2)=3(2)2-10(2)+7
=3(4)-10(2)+7
=12-20+7 =-1
f(-1)=3(-1)2-10(-1)+7
=3(1)+10+7
=3+10+7
=20

f(x) =x3-5x2+7x-11
f|(x)=3x2-10x+7
f|(0)=3(0)-10(0)+7
=7
f|(2)=3(2)2-10(2)+7
=3(4)-10(2)+7
=12-20+7 =-1
f(-1)=3(-1)2-10(-1)+7
=3(1)+10+7
=3+10+7
=20
