Determine the enthalpy change of the following reaction 2KCl
     Determine the enthalpy change of the following reaction: 2KClO_3 rightarrow 2KCl + 3O_2 Given enthalpies: KClO_3: -391.4 kJ/mol O_2: 0 kJ/mol KCl: -436.7 kJ/mol  90.6 kJ/mol  B. -45.3 kJ/mol  C. 45.3 kJ/mol  D. -90.6 kJ/mol  E. 828.1 kJ/mol 
  
  Solution
Enthalpy of reaction = Enthalpy of formation of products - Enthalpy of formation of reactants
=-436.7+0 - (-291.4)=-45.3kJ/mol

