Determine the enthalpy change of the following reaction 2KCl
Determine the enthalpy change of the following reaction: 2KClO_3 rightarrow 2KCl + 3O_2 Given enthalpies: KClO_3: -391.4 kJ/mol O_2: 0 kJ/mol KCl: -436.7 kJ/mol 90.6 kJ/mol B. -45.3 kJ/mol C. 45.3 kJ/mol D. -90.6 kJ/mol E. 828.1 kJ/mol
Solution
Enthalpy of reaction = Enthalpy of formation of products - Enthalpy of formation of reactants
=-436.7+0 - (-291.4)=-45.3kJ/mol
