Consider the reaction N2g 3H2g 2NH3g Suppose that at a part

Consider the reaction N2(g) + 3H2(g) 2NH3(g) Suppose that at a particular moment during the reaction, molecular hydrogen is reacting at the rate of -0.067 Mis. a) At what rate is ammonia being formed? Mis (b) At what rate is molecular nitrogen reacting? Mis

Solution

rate of reaction in terms of H2
rate of reaction = (-1/3)*d[H2]/dt

a)
rate of reaction in terms of NH3
rate of reaction = (1/2)*d[NH3]/dt

Equate the given reaction with this:
(1/2)*d[NH3]/dt = (-1/3)*d[H2]/dt
d[NH3]/dt = (-2/3)*d[H2]/dt
d[NH3]/dt = (-2/3)*(-0.067 M/s)
d[NH3]/dt = 0.0447 M/s
Answer: 0.0447 M/s

b)
rate of reaction in terms of N2
rate of reaction = (-1)*d[N2]/dt

Equate the given reaction with this:
(-1)*d[N2]/dt = (-1/3)*d[H2]/dt
d[N2]/dt = (1/3)*d[H2]/dt
d[NH3]/dt = (1/3)*(-0.067 M/s)
d[NH3]/dt = -0.022 M/s
Answer: -0.022 M/s