15 of 15 Part A An experiment requires 512 g of ethylene gl

15 of 15 > Part A An experiment requires 51.2 g of ethylene glycol, a liquid whose density in Sl units is 1114 kg/m3 Rather than weigh the sample on a balance, a chemist chooses to dispense the liquid using a graduated cylinder. What volume in mililiters of the liquid should be used? Express your answer to three significant figures and include the appropriate units. v 40.4 mL Submit xIncorrect; Try Again; 4 attempts remaining Return to Assignment Provide Feedback

Solution

Mass of ethylene glycol = 51.2 g = 51.2 Kg / 1000 = 0.0512 Kg

Density = 1114 Kg/m^3

Volume of ethylene glycol required = 0.0512 Kg / 1114 Kg/m^3 = 4.596 * 10^-5 m^3

We know 1 m^3 = 10^6 ml

So volume of ethylene glycol required = 4.596 * 10^-5 * 10^6 ml = 45.96 ml