Use standard reduction potentials to calculate the equilibri

Use standard reduction potentials to calculate the equilibrium constant at 25 C for decomposition of hydrogen peroxide.
2H2O2 (l) -> 2H20 (l) + O2 (g)


K=

Solution

Geez, You\'re both way off.


The answer is K= 3.45 *10^36


Here\'s how:

Equaton: ln[k]=nFEo/RT

Where n=#mol (of electrons transferred), F= Ferday\'s constant (96500 c/sec), Eo= cell potential, R=8.314J (ideal gas constant) and T=temp (Standard is 25C or 298K)

Eo= 1.08 (got by sum of reduction potential of products - sum of reduction potential of reactants) which is usually found in the appedix of your chem book.


So,

ln[k]=(2)(96500)(1.08)/ (8.314)(298)

ln[k]=84.1307

Take the e^ of both sides to cancel out ln


so e^84.1307= 3.45*10^36

Your answer.

 Use standard reduction potentials to calculate the equilibrium constant at 25 C for decomposition of hydrogen peroxide. 2H2O2 (l) -> 2H20 (l) + O2 (g) K=Sol

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