We are finding intervals of monotonicity of fx sqrt9 x2 on
We are finding intervals of monotonicity of f(x) = sqrt(9 - x2), on [-3,3]
We now know f \'(x) = 0
Now find the critical points and singularities of f;
that is, the points where f\' is zero or does not exist.
Critical Point and Singularity List:
We now know f \'(x) = 0
Now find the critical points and singularities of f;
that is, the points where f\' is zero or does not exist.
Critical Point and Singularity List:
Solution
f(x) = sqrt(9 - x2) f\'(x)=-x/sqrt(9 - x2) critical points x=0,3,-3 (0,3),(3,0),(-3,0)![We are finding intervals of monotonicity of f(x) = sqrt(9 - x2), on [-3,3] We now know f \'(x) = 0 Now find the critical points and singularities of f; that is, We are finding intervals of monotonicity of f(x) = sqrt(9 - x2), on [-3,3] We now know f \'(x) = 0 Now find the critical points and singularities of f; that is,](/WebImages/39/we-are-finding-intervals-of-monotonicity-of-fx-sqrt9-x2-on-1119274-1761595236-0.webp)