We are finding intervals of monotonicity of fx sqrt9 x2 on

We are finding intervals of monotonicity of f(x) = sqrt(9 - x2), on [-3,3]

We now know f \'(x) = 0

Now find the critical points and singularities of f;
that is, the points where f\' is zero or does not exist.

Critical Point and Singularity List:

Solution

f(x) = sqrt(9 - x2) f\'(x)=-x/sqrt(9 - x2) critical points x=0,3,-3 (0,3),(3,0),(-3,0)
We are finding intervals of monotonicity of f(x) = sqrt(9 - x2), on [-3,3] We now know f \'(x) = 0 Now find the critical points and singularities of f; that is,

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