d 4 points Ouabain specifically inhibits only Na K ATPase ac
Solution
Thank you for asking the question, it also taught me the function of ATPase.
The \"one sentence statement\" is however not that apt but it completely makes sense.
Ouabain can be used as an estimate of energy associated with the turnover of the Na+K+ ATPase, since Ouabain is specifically known to inhibit the function of Na+K+ATPase. Therefore, measurement of decrease in the rate of oxygen consumption after the additon of Ouabain were used to quantitate energy utilization by the Na+K+ATPase.
Na+K+ATPase is popular for utilizing energy and consumption of oxygen and ATP is popular for supply of energy.
The Na+/K+ pump illustrates \"active transport\" since it moves Na+ and K+ against their concentration gradients. That is because there is already a high concentration of Na+ outside the cell and a high concentration of K+ inside the cell. In order to move the ions (Na+ and K+) againts their gradients, energy is required. This energy is supplied by ATP (adenosine triphosphate). An ATP molecule floating inside the cell, binds to the pump transferring some energy to it. As the energy is used, the ATP falls off and having lost its energy it is converted into ADP (adenosine diphosphate).
Therefore, summing up, the statement given as an answer is meaningful as it states that 2/3 of ATP i.e., 66% of ATP(which supplies energy and oxygen level) is utilized by Na+K+ATPase (which consumes energy resulting in loss of energy and oxygen level).
THANK YOU.
